BEECH GROVE — Police responded to a Walmart on the city's southern end after a gunshot was fired inside the store during a disturbance between two people, an official said.
No one was struck by gunfire, and police have taken in those involved in the altercation to determine what exactly occurred, said Beech Grove Deputy Police Chief Robert Mercuri.
Officers were dispatched at about 9 p.m. to the store, located at 4650 S. Emerson Ave. for a report of a possible shooting. Employees and customers were evacuated from the building around that time.
After police arrived, they discovered two people, both females, were involved in an altercation and at one point a single shot was fired. A third person tried to intervene in the dispute and got into a physical struggle, which left her with minor injuries, Mercuri said.
No employees were involved.
Police do not know the circumstances of the argument or exactly what occurred prior to a shot being fired. At this time it's not clear if either person involved in the dispute has been placed under arrest.
"The people involved are being detained by law enforcement while the investigation continues," Mercuri said.
Additional details were not immediately available.
-
Hancock County non-profit serving women sees sharp rise in need
As uncertainty continues, leaders at the Women’s Resource Center say they’re preparing for that number to grow, and they’re calling on the community to help them continue meeting demand.
Two 17-year-olds dead following shooting on Indy's north side
One juvenile is dead, and another is in critical condition following a shooting on the north side of Indianapolis on Sunday afternoon, police said.
Pacers snap 5-game losing streak with a 114-109 win over the Warriors
The Indiana Pacers snapped a season-opening five-game losing streak with a 114-109 victory over the Golden State Warriors on Saturday night.
IMPD safely finds missing 18-year-old
The eighteen-year-old was last seen on foot on Sunday, November 2, 2025, at approximately 9:15 a.m. in the 1000 block of N. Graham Avenue.